1p^2-12p+3=4

Solution for 1p^2-12p+3=4 equation:

1p^2-12p+3=4

We move all terms to the left:

1p^2-12p+3-(4)=0

We add all the numbers together, and all the variables

p^2-12p-1=0

a = 1; b = -12; c = -1;
Δ = b2-4ac
Δ = -122-4·1·(-1)
Δ = 148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{148}=\sqrt{4*37}=\sqrt{4}*\sqrt{37}=2\sqrt{37}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{37}}{2*1}=\frac{12-2\sqrt{37}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{37}}{2*1}=\frac{12+2\sqrt{37}}{2}
$